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L(u,v) are true if you're on a 0 in u and a 1 in v, and false otherwise. If you run out of letters in both at the same time, then uv and both l and d are false. If you run out of letters in u and v still has more, d is true. If you run out of letters in v and u still has more, d is false. M - homework-consultation Center. newsolutionpowerweb m, this is a consultation property to guide on homework, assignments and any writing jobs you may have. We also have a library for. Domain info, domain created 8 months ago, latest check 1 month ago. Server location, united States, mywot, trust, n/A.
If they are of the same length, there evernote is a first difference between u and v and a first difference between v and. Whichever of these comes first (they cannot come at the same time, as there are only two possible values for the letter in question that very letter is the first difference between u and w and forces L(u,w) to be true. The argument for d is similar. Consider the first difference between u and v and the first difference between v and w, considering the prefix relation to be a difference at the end. The earlier of these two differences is also a difference between u and w, forcing D(u,w) to be true. L and d are both total - the argument for antisymmetry above shows that if u and v are different, either L(u,v) or L(v,u) must be true and either D(u,v) or D(v,u) must be true. Both L(x,y) and D(x,y) are computable because it is easy for a tm to decide them as follows. First check the length of each and return true for l if x is shorter and false for l if x is longer.
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L and d advantages are both anti-reflexive because L(x,x) and D(x,x) are both clearly false - you can't find a t such that x starts with both t0 and. L and d are both anti-symmetric. For l, clearly if one is shorter the other is not, and if the first difference in the strings has a 0 for u it cannot also have a 0 for. For d, if u is a prefix of v then D(v,u) is impossible because u and v agree until u ends. And again, if the first difference has a 0 for u it cannot also have a 0 for. L and d are both transitive. If L(u,v) and L(v,w) are both true, l(u,w) follows immediately if the three strings are not all of the same length.